Assume momentum is conserved in this case Cart A of mass 0.737kg is moving on a

Question

Assume momentum is conserved in this case Cart A of mass 0.737kg is moving on a leveled track with a speed 0.458m/s. It then collides with cart B of unknown mass. After collision, the two carts are stuck together with a speed 0.246m/s. What is the mass of cart B (in unit of kg)? QUESTION 4 2.5 points Save Answer Assume momentum is conserved in this case A cart of mass 0.589kg is moving on a leveled track with a speed 0.433m/s. It then collides with another cart of mass 0.534kg, and become stuck with it. What is the speed in (m/s) after collision?

Explanation / Answer

Applying momentum conservation for the collision,

pi = pf

(0.737 x 0.458) + (mB x 0) = (0.737 + mB)(0.246)

mB + 0.737 = 1.372

mB = 0.635 kg ....Ans

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Applying momentum coservation,

(0.589)(0.433) + (0.534 x 0) = (0.589 + 0.534)v

v = 0.227 m/s .....Ans

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