M2 4. The two masses in the sketch above are on a horizontal, frictionless is 13

Question

M2 4. The two masses in the sketch above are on a horizontal, frictionless is 13 N, Mi-13 kg and Ma 2.1 kg. What is the force of Mi on Ma a) 3.8 N b) 50N c) 80N d) 13 N e) 21 N Ma:2.1 )4at the ends of the rope make with the borizontal? s at rest at the center of a rope. If the tension in the rope is b) 24° c) 35 d) 39° e) 55 T- 620 6. Two carts are moving on a horizontal frictionless track. Initially one is moving to the left the two carts as and the other to the right. They collide and stick together. If we regard our system, which of the following statements is true? a The momentum of the system is conserved, but the mechanical energy is The mechanical energy of the system is conserved, but the momentum is not. not. b) c) Neither the momentum nor the mechanical energy is conserved. d) Both the momentum and the mechanical energy are conserved. e) Not enough information is given to determine what is conserved. m 2 mi A0.10 kg ball of clay traveling north at 3.0 m/s collides with a 020 kg ball of clay traveling west at 4.0 n's. The collision is completely inelastic. What is the direction of motion of the resulting 0.30 kg clay blob? 7. a) 21° north of west m b) 82° west of south c)54° west of south 0.20 kg· m n= 3 0.3 V- 3.0m/ d) 82° east of south e 54° east of north 4.0 mls s 0.20

Explanation / Answer

4. a = F / (M1 + M2) = 13 / (1.3 + 2.1)

a = 3.82 m/s^2

F12 = M2 a = 2.1 x 3.82 = 8.0 N

Ans(c)

5. in vertical, F_net = 2 T sin(theta) - m g = 0

2 (620) sin(theta) = (52)(9.8)

theta = 24 deg Ans(b)

6. Ans(a)

7. (0.10 x 3j) + (0.20 x - 4i) = (0.1 + 0.20) v

v = - 2.67i + 1j

theta = tan^-1(1/2.67) = 21 deg North of west

Ans(a)

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