I am not understanding the first, second or third starred conclusion questions.
ID: 2304877 • Letter: I
Question
I am not understanding the first, second or third starred conclusion questions.PROCEDURE masses of the two smaller gliders of equal mass (make them equal!) will be mi, and m2, and the mass of the larger glider will be my. Use SI units. Determine the masses of the gliders and record them in a DATA Table supplied. The ermine the length, L, of each glider and record in the DATA Table. Use SI units. so that the gliders interrupt the photogate beam as they enter and leave the collision area. De liming on will be done by placing photogate timers along the air track near the point of The velocities of the gliders can then be determined by dividing the length of the glider (the distance it travels) by the interrupt time recorded by the photogate timer. The timers have a memory mode so that they can record times of two cart passages by proper use of the COLLISION BETWEEN TWO GLIDERS OF EQUAL MASS, WTH ONE NITIALLY AT REST CASE?: 1. With one of the gliders (m2) of equal mass stationary at the center position of the air track, shove the other glider (m) toward the stationary glider. See the diagram below. (NOTE: In general, the collisions will be more free of external forces if glider velocities are kept relatively low, but not too low.) A trial run should show that mi will stop at the point of the collision and that m2 will move forward at the same speed that mi used to have. 2. Determine the time it takes for mi to travel through its photogate timer as it approaches m2, and the time it takes for m to travel through the other photogate timer after the collision. These two times should be nearly equal (Case 1 only!). TEE PHOTOGATE TIMER STOPS WORKING, TRY CLOSING THE SHADES. 3. Compute the total momentum before and after the collision and the percent difference in these values (let the initial values play the role of the accepted values). Be careful with the signs given velocity and momentum values. Which direction is positive; which negative? Do the gliders move in the same or in opposite directions? If the percent difference is too large, go back to the air track and repeat another trial for this case. M2 CASE : mm CASE 2: mm
Explanation / Answer
Conclusion 1)Error (a) when collision occur betwwen two masses there is always a loss of energy through heat and sound and no collision is perelastic collision.
(b)momentum is not conserved before collision because surface and air always resist and there dragging effect will reduce momentum and energy
Energy momentum is not conserved in this one dimensional elastic collision.
Conclusion 2)Glider in both cases before collision are moving in same direction but in case 1 M1 is in rest after the collision but the other mass in case 1 after collision move with approximately same speed in the same dirction but it experience acceleration during collision but after collision it dose not experience acceleration.
It is not accelerating as passed throug photogate timer but deaccelerate as passed through beccause surface and air will produce deacceleration. this will effect our momentum and energy conservation .
Conclusion 3)Energy is not conserved in any case this will lost as heat and sound and frictional heat form.
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