(50%) Problem 1 : Rod AB, which is a conductor of length L-0.125 m and resistanc

Question

(50%) Problem 1 : Rod AB, which is a conductor of length L-0.125 m and resistance R-160 ?, lies on a horizontal rectangular conducting loop, thus creating two conducting loops, labeled 1 and 2, as in the diagram. The resistance of the rectangular loop is ncgligible. The setup is located in a uniform, vertically directed magnetic field of strength B-0.85 T, as shown in the diagram. The rod is moving to the right at speed v- 0.75 m/s Otheexpertta.com 20% Part(a) Find the emf. El, in volts, that is induced in loop ! 20% Part (b) what is the direction of the induced current in loop 1? 20% Part (c) Find the emf, E2, in volts, that is induced in loop 2 20% Part (d) What is the direction of the induced current in loop 2? 20% Part (e) What is the current, I, in amperes, flowing through the rod? Grade Sunmarv Deductions Potential -0.000498 4% 96% 7 89 HOME cos() cotan asinacos0 atan() acotan()sinh() cosh cotanh O Degrees O Radians sin Submissions Attempts remaining: 8 (2% per attempt) detailed view 0 END 2% 2% BACKSPACE DELI CLEAR Submit Hint Feedbachk I give up! llints: 0% deduction per hint. I lints remaining: 1 Feedback: 0% deduction per feedback

Explanation / Answer

(A) e1 = B L v = 0.85 x 0.125 x 0.75

e1 = 0.080 Volt

(B) field is into the page and flux is increasing.

so field due to induced current will be out of page.

Ans: COunter clockwise

(C) e2 = 0.080 Volt

(D) in loop 2, flux is decreasing.

so induced current will be clockwise.

(E) e = e1 + e2 = 0.159 Volt

I = e / R = 0.160 / 160

I = 0.001 A  

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.