An LRC series circuit with R = 120 ? , L = 18 mH , and C = 1.4 ?F is powered by

Question

An LRC series circuit with R = 120 ? , L = 18 mH , and C = 1.4 ?F is powered by an ac voltage source of peak voltage V0 = 430 V and frequency f = 480 Hz .

Part A) Determine the peak current that flows in this circuit. Express your answer using two significant figures.

Part B)Determine the phase angle of the source voltage relative to the current. Express your answer using two significant figures.

Part C) Determine the peak voltage across R. Express your answer using two significant figures.

Part D) Determine the phase angle of the voltage across R relative to the source voltage. Express your answer using two significant figures. Part E) Determine the peak voltage across L. Express your answer using two significant figures.

Part F)Determine the phase angle of the voltage across L relative to the source voltage. Express your answer using two significant figures. Part G) Determine the peak voltage across C. Express your answer using two significant figures.

Part H) Determine the phase angle of the voltage across C relative to the source voltage.

Explanation / Answer

(A) R = 120 ohm

XL = 2 pi f L = 2 x pi x 480 x 0.018

XL = 54.3 ohm

Xc = 1 / (2 pi f C) = 1/(2 x pi x 480 x 1.4 x 10^-6)

Xc = 236.84 ohm

Z = sqrt[R^2 + (XL - XC)^2] = 218 ohm Or 220 Ohm

I_peak = V_peak / Z = 1.97 A Or 2.0 A

(B) phi = tan^-1((XL - XC)/R) = - 57 deg  

(C) VR = I R = 236 Volt Or 240 Volt

(D) 0

(E) VL = 107 Volt Or 110 Volt

(F) 90 deg  

(g) Vc = 467 Volt Or 470 Votl

(h) - 90 deg

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