Object O1 is 16.0 cm to the left of a converging lens with a 11.3-cm focal lengt

Question

Object O1 is 16.0 cm to the left of a converging lens with a 11.3-cm focal length. A second lens is positioned 10.0 cm to the right of the first lens and is observed to form a virtual image at the position of the original object O1.

Please help with Part B!

(a) What is the focal length of the second lens? -13.6 Correct: Your answer is correct.

(b) What is the overall magnification of this system? 5.04 AND 2.63 Incorrect: Your answer is incorrect.

(c) What is the nature (i.e., real or virtual, upright or inverted) of the final image? virtual and upright Correct: Your answer is correct.

Explanation / Answer

(A) for first lens,

f1 = 11.3 cm

object distance, p1 = 16 cm

1/f1 = 1/p1 + 1/q1

q1 = 38.5 cm

this image will work as object for second lens,

p2 = 10 - 38.5 = - 28.5 cm

image distance, q2 = - (10 + 16) = - 26 cm

1/f = 1/p + 1/q

f = - 13.6 cm

(b) m = m1 m2 = (-q1/p1)(-q2/p2)

m = (38.5 / 16) (-26/-28.5)

m = + 2.20

(C) Virtul, Upright

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.