While he is in mid air, a cliff diver throws a 0.2kg mass ball horizontally with

Question

While he is in mid air, a cliff diver throws a 0.2kg mass ball horizontally with respect to himself with a speed of 10m/s in the positive direction. At the instant he threw the ball his downward speed was 10 m/s. Define the vertical and horizontal positions of the ball with respect to the diver as 0 at the instant the diver released the ball. Ignore air resistance for this problem.

(a) If we measure position with respect to the diver, what is the vertical position in meters of the ball 1 second after the diver threw it?

(b) If we measure position with respect to the diver, what is the vertical velocity in m/s of the ball 1 second after the diver threw it?

(c) If we measure position with respect to the diver, what is the horizontal position in meters of the ball 1 second after the diver threw it?

(d) If we measure position with respect to the diver, what is the horizontal velocity in m/s of the ball 1 second after the diver threw it?

(e) If the ball were on a scale and the diver threw both of them so that they traveled together with the ball on the scale, what weight in Newtons does the scale read for the ball?

(f) Is the motion of the ball with position measured with respect to the diver what one would expect for an inertial reference frame with no forces on the ball?

Explanation / Answer

(A) both have same initial vertical velocity and same vertical acceleration.

so ball is at rest relative to diver (in vertical)

y = 0

(B) vy = 0

(C) in horizontal, v_ball = 10 m/s and v_diver = 0

v_ball wrt diver = 10 m/s

x = v_relative t = 10 x1 = 10 m ....Ans

(D) v_x = 10 m/s

(E) both have same acceleration so N - m g = m a

N = 0  

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