help please #11 2018 Ch 32 Begin Date: 4/13/2018 12:01:00 AM .. Due Date: 4,1820
ID: 2305161 • Letter: H
Question
help please
#11 2018 Ch 32 Begin Date: 4/13/2018 12:01:00 AM .. Due Date: 4,182018 11:59:00 PM End Date: 4/20/2018 11:59:00 PM (11%) Problem 9: In the AC circuit shown in the figure the values are lms-120 V, C- 190 uF, and R-9.9 2. The frequency of the voltage source is 57 Hz. The voltage across the resistor in the circuit leads the source voltage by 14.4° Assignment Status Click here for detailed view Find the inductance of the inductor, in millihenrys Problem Status 1 Completed Potential 100% sin) tan0 Attempts retiaining O Degrees O RadiansExplanation / Answer
voltage across resistor or current leads the voltage.
so this is capacitive circuit.
Xc > XL
tan14.4 = (XC - XL) / R
Xc = 1 / (2 pi f C) and xL = 2 pi f L
9.9 tan14.4 = (1 / (2 x pi x 57 x 190 x 10^-6)) - (2 x pi x 57 x L)
L = 0.0339 H OR 33.9 mH ....Ans
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