001 (part 1 of 8) 10.0 point:s Assume you are on a planet similar to Earth where

Question

001 (part 1 of 8) 10.0 point:s Assume you are on a planet similar to Earth where the acceleration of gravity is approxi- 5. m mately 10 m/s and the positive directions for displacement, velocity, and acceleration are 6. m upward. At time t = 0 s, an elevator is at a displace- ment of x-0 rn with a velocity of U-0 m/s. A student whose normal weight is 400 N stands on a scale in an elevator and records the scale reading as a function of time. The data are shown in the graph. 50 kg 60 kg 7. m ? 10 kg 8. m* 80 kg 40 kg 9. m 003 (part 3 of 8) 10.0 points Calculate the acceleration of the elevator dur- z 800 600 400 200 ing the fourth 5 s interval (from 15 s to 20 Answer in units of m/s 004 (part 4 of 8) 10.0 points 10 15 20 time (s) Choose the correct plot for acceleration vs time. In which direction does the force due to the scale act on the student? 10 1. left 2. forward 3. right 4. The net force on the student is zero, so 0 510 15 20 time (s) the force the scale exerts on the student has no direction 10T. 5. backward 6. up 7. down -10 0 510 15 20 time (s) 002 (part 2 of 8) 10.0 point:s What is the mass of the student?

Explanation / Answer

PART: 1 :

Here the scale reading varies as a function of time. As elevator moves the force acting on student will change but the direction will change accordingly to the direction of elevator. Force due to scale will always be in upward direction as studetns's force acting on downward direction.

PART:2 :

Here, F = mg = 400 N

g= 10 m/s2

It gives mass of a student : m = F/g = 400/10 = 40 kg

PART:4

It is same as N versus time, as N =ma and m remains constant so grpah of acceleration versus time will be same as N versus time.

Correct answer is 2.

PART : 8

POSITION versus TIME:

correct option is : 2.

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