PartA The current in a 100 watt lightbulb is 0.830 A. The filament inside the bu

Question

PartA The current in a 100 watt lightbulb is 0.830 A. The filament inside the bulb is 0.100 mm in diameter. You may want to review (Pages 750-752) For help with math skills, you may want to review: Rearrangement of Equations Involving Multiplication and What is the current density in the filament? Express your answer with the appropriate units. View Available Hint(s) Division 10-8 A Submit Previous Answers X Incorrect; One attempt remaining; Try Again Part B What is the electron current in the filament? Express your answer with the appropriate units. View Available Hint(s)

Explanation / Answer

here,

current , I = 0.83 A

diameter , d = 0.1 mm = 1 * 10^-4 m

A)

the current density , J = I /(pi * (d/2)^2)

J = 0.83 /( pi * (1 * 10^-4 /2)^2) A/m^2

J = 1.06 * 10^-8 A/m^2

b)

the electron current , I' = I /e

I' = 0.83 /( 1.6 * 10^-19) electrons /s

I' = 5.2 * 10^18 electrons /s

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