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Pushing on a mass A mass m starts at rest. Starting at t = 0, you push on it wit

ID: 2306509 • Letter: P

Question

Pushing on a mass A mass m starts at rest. Starting at t = 0, you push on it with a constant force F. How much t does it take for the mass to move a distance x? (F, t, and x here are measured in the lab frame.) Check that your result is reasonable when x rightarrow 0. After a very long time, m's speed will approach c. It turns out that it approaches c sufficiently fast so that after a very long time, m will remain (approximately) a constant distance (as measured in the lab frame) behind a photon that was emitted also at t = 0 from the starting position of m. What is the distance?

Explanation / Answer

(a) If a is the acceleration

F=ma

a = F/m

x = ut+(1/2)at2 [u=0]

x = (1/2)at2

t = (2ax)1/2 = (2Fx/m)1/2 (1)

(b) when v = c

v = u + at

Using eq (1)

c = 0 + (F/m)(2Fx/m)1/2   

c2 = (F/m)2(2Fx/m) = 2F3x/m3

x = m3c2 /2F3

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