Problem-1 rying P, 8000 lb and P, 2000 lb is shown below. Table shows A single c
ID: 2311452 • Letter: P
Question
Problem-1 rying P, 8000 lb and P, 2000 lb is shown below. Table shows A single cell-6 flange tapered beam ca stringer areas and end point coordinates of each stringers relative to global xyz coordinate system. centroid at station x-200 relative to global coordinates is given by Xs* 200 in, y: 5 in and ZG=-93.33 Beam cross section at station, x-200 is shown below. Use: .-(1/MrlwHM1tMMJy + (M,4 + Mayt)2) 1. Determine moment of Inertia, 11, , and about centroidal axis at station 200 2. Determine the vector moment, M of the loads about G in terms of IL, J, k using Ma - r x F 3. Determine bending stresses and axial load in each stringer at station, x- 200 4. Determine in plane forces produced by flange inclination at x 200 5, Using &P; method, determine shear flow at station x-200 in 8000 Ib t0° 24 2.5* 2000 tb 20 20 120 30 Station 0 Station 200 Stringer Area 0.5 1.0 1.5 1.5 1.0 0.5 10 10 10 30 30 -120 -120 200 1.5 in.2 1.0 in 2 40 05 in2 G 2 10 in. 1.5 in. 10 in. 0.5 in.2Explanation / Answer
1) Ix =bd3/12
=200*103/12 =16666.66in4
Iy = db3/12 =10*2003/12
=6.66*106 in4
Iz= (Ix +Iy) =(16666.66 +6.66*106) =6.67*106 in4
2)M=8000*26.67" i+2000*5"j
=213.36*103i+10000j
3)M/I =/y
(wl2/8 )/(16666.67)*5"=
=119.999Kip
axial load at each section
FA1=FA6=119.99*.5=59.97lbs
FA2=FA5=119.99*1=119.99lbs
FA3=FA4=119.99*1.5=179.985lbs
5)P=F2-F1=119.99-59.97=60.02lbs
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