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1. Using the flowra te data presented below, determine the volume of an equaliza

ID: 2311654 • Letter: 1

Question

1. Using the flowra te data presented below, determine the volume of an equalization tank and determine the effect of equalization on the hourly BOD concentration. Time Period Avg. flowrate during the time period, mis Avg BOD concentration during the time period, mg/L 150 115 1:002:00 2:003:00 3:004:00 4:005:00 5:006:00 6:00 7:00 7:008:00 8:009:00 9:0010:00 10:00 11:00 11:00 12:00 12:00 13:00 13:00 14:00 14:00 15:00 15:00 16:00 16:00 17-00 17:00 18:00 18:00 19:00 19:00 20:00 20:00 21:00 21:00 22:00 22:00 23:00 23:00 0:00 0.180 0.160 0.160 0.185 175 0.480 190 180 0.331 0.315 0.320 0.346 0.392 0.360 180

Explanation / Answer

FROM TABLE WE CAN SEE

VOLUME = 471.66 m3 = 471660 L

and equalization BOD= 187.13 mg/L

if we compare with hourly BOD it is more for first 9 hours BOD but less for Remaining BOD 16-19 and 24 hours

time past 00 hr flow rate BOD Mg/L Total flow m^3 Total flow L Bod mg 1 0.300 150 18.000 18000 2700000 2 0.220 115 13.200 13200 1518000 3 0.180 75 10.800 10800 810000 4 0.160 50 9.600 9600 480000 5 0.160 45 9.600 9600 432000 6 0.185 60 11.100 11100 666000 7 0.240 90 14.400 14400 1296000 8 0.300 130 18.000 18000 2340000 9 0.385 175 23.100 23100 4042500 10 0.440 200 26.400 26400 5280000 11 0.480 215 28.800 28800 6192000 12 0.480 220 28.800 28800 6336000 13 0.460 220 27.600 27600 6072000 14 0.420 210 25.200 25200 5292000 15 0.390 200 23.400 23400 4680000 16 0.355 190 21.300 21300 4047000 17 0.311 180 18.660 18660 3358800 18 0.315 170 18.900 18900 3213000 19 0.320 175 19.200 19200 3360000 20 0.346 210 20.760 20760 4359600 21 0.362 280 21.720 21720 6081600 22 0.392 305 23.520 23520 7173600 23 0.360 245 21.600 21600 5292000 24 0.300 180 18.000 18000 3240000 Total 471.66 471660 88262100 average BOD =
Total BOD/T.VOL (mg/L) 187.1307722