Hwk1 due 9/2/16 EGR251 Statics Remember: neat, single sided, non-lined (unless e

Question

Hwk1 due 9/2/16 EGR251 Statics Remember: neat, single sided, non-lined (unless engineering paper), stapled, and boxed-answer homework. Note: for this assignment, please convert units by hand instead of by calculator or computer. You can use a calculator for the math, of course. DeJong1.1-Solve for a and b in the Trigonometry example in the syllabus DeJong1.2-Solve for x, y, and z in the Algebra example in the syllabus anefad with hemba unuts For example for fa), convert Ib to N, and 1.4 Ah, unit conversions. Use the conversion factors on the inside cover of the book and cancel the units as you go. For example, for (a), convert Ib to N, and ft to m. Be careful with the cubed units! 1.13-Same idea. Feels sluggish, eh?

Explanation / Answer

1.1

Weight (N) = Mass (kg) × Acceleration Due To Gravity (9.81 m/s2)

(a) Mass= 8 kg

Weight (N) = 8 kg ×9.81 m/s2 = 73.48 N

(b) Mass= 0.04 kg

Weight (N) = 0.04 kg ×9.81 m/s2 = 0.392 N

(c) Mass= 760 Mg = 760 × 10 -6 kg

Weight (N) =  760 × 10 -6×9.81 m/s2 = 0.007456 N

1-2

a) kN/S = 103N/10-6s =109 N/S

b) Mg/mN = 10-6Kg/10-3N = 10-3 kg/N

c) MN/(kg,ms) = 106N/(kg. 10-3s) = 109 N/(kg.s)

1-3

1 ft = 0.3048 m

1 lb = 0.4536 kg

1 kilogram is equal to 9.81 newtons n earth

a) So, 200 lb.ft = 200× 0.4536 kg× 0.3048 m= 27.651 kg.m = 271.261 N.m

b) 1 ft = 0.3048 m , So 1 ft3 = 0.0283 m3

1 lb = 0.4536 kg= 4.45 N = 0.00445 kN

So, 350 lb/ft3 = 350× 0.00445 kN/0.0283 m3 = 50.035 kN/m3

c) 1 h = 3600 s

1 ft = 304.8 mm

8 ft/h = 8 ×  304.8 mm/ 3600 s = 0.677 mm/s

1-4

1 slug = 14.594 kg

1 ft3 = 0.0283 m3

So, 5.26 slug/ft3 = 5.26 × 14.594 kg / 0.0283 m3 = 2712.524 kg/m3

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