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2) In this simplified network schedule, tasks A, D, E, and F are the critical pa

ID: 2437193 • Letter: 2

Question

2) In this simplified network schedule, tasks A, D, E, and F are the critical path. Based on this information, select the correct statement.
(IMAGE DESCRIPTION: Network diagram displays 6 tasks. Task A is at the start with zero float and it is a predecessor for tasks D and B. Task D has zero float and is a predecessor for tasks E and C. Task C has 6 days of float and is a predecessor for task F. Task E has zero float and is also a predecessor for task F. Task B has 6 days of float and is a predecessor for tasks D and C. Task C has 6 days of float and is a predecessor for task F.)
A.) Tasks A, D, E, and F determine the longest project duration and have the highest potential for delaying the project.
B.) Tasks B and C have excessive float, so they are not critical to the network schedule.
C.) Tasks A, D, E, and F are the tasks with the most flexibility in the network, so when they slip there is typically no impact to the end date.
D.) If tasks A, D, E or F slip, the project end date will not slip and therefore they are critical. Float = 0 Float = 0 Float = 0 Float = 6 Float=6 Float = 0

Explanation / Answer

2) Answer : " A.) Tasks A, D, E, and F determine the longest project duration and have the highest potential for delaying the project."

=> The path of Tasks ADEF is a longest and critical one and any delay in execution of the tasks will delay the project. The permitted float delay time is zero, so any delay in these tasks will be very critical.

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