Clay is a 24 year old, 6 feet, 220 pound, sedentary male. Diet analysis revealed

Question

Clay is a 24 year old, 6 feet, 220 pound, sedentary male. Diet analysis revealed Clay's average caloric intake for three days was 6000 calories and he's maintaining his current body weight. He's also averaged 900 grams of carbohydrate, 166 grams of fat, and 226 grams of protein for that three-day period. Clay used to rodeo and is a fairly strict vegetarian, spanning the spectrum of vegan to lactovegetarian to lacto-ovo-vegetarian depending on his current mood. He also avoids alcohol and various forms of tobacco. His vitamin B12 intake averaged 0.24 ?g/day. Clay's recommendation for B12 is 2.4 ?g/day.

After several tries, Clay successfully completes an underwater weighing body test. His body density is 1.053 g/ml and his body fat percentage is 20.2%. How many pounds of adipose tissue does Clay have?

Based on his BMI and body composition, how would you classify his weight? Are you able to make the same classification based on each or do they differ?

Explanation / Answer

Total weight of Clay = 220 pounds

Body fat percentage = 20.2% in decimal it will be (0.20)

Total Adipose tissue = weight *body fat percentage= 220* 0.20 = 44 pounds.

BMI calculation:

Body weight in kg = 90.7

Height in meters = 1.82

BMI = Weight in kg = 90.7 = 27.04

height in meter square 3.31

According to the BMI of Mr.Clay, his weight can be classified as overweight (range of BMI for overweight is 25.0-29.9)

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