In this simulation, you established the fitness of the aa allele as 0, removing

Question

In this simulation, you established the fitness of the aa allele as 0, removing all aa individuals from the breeding population. This may be realistic in the case of serious genetic disease, but selection is not always so drastic. In the case of coquinas on the beach, white shells may suffer a measurable disadvantage due to higher bird predation, but their fitness is obviously not zero. Some white clams do survive to reproductive age. Suppose predation rates on white clams were not total, but did occur at twice the rate of predation on purple-rayed clams. how would you alter this procedure to simulate a 50% survival rate of the aa genotype? How would you expect this change in the simulation rules to affect the outcome?

Explanation / Answer

Well this is a rough guess: Assuming r=0.5 is of the offspring then 0.2/0.5 is the fraction of 0.4 of one offspring. so it requires 2.5 of this 0.2 to be equal to an offspring which is of 0.5 0.2 x = 0.5 x = 2.5 Trophic level is not used to measure a species rarity. trophic level is the place of an organism in a food chain (such as primary consumer, secondary consumer, etc.). The other three detail where you can find an organism and how many you will find there. For example a species is rare if it is found in a narrow range of locations and has few numbers. If an organism has a very specific habitat, then there is a limited number of places where it can thrive. Hope this helps!

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