The weight of a 10 lbm is measured at a location where g = 32.1 ft/sec^2 on a sp
ID: 249483 • Letter: T
Question
The weight of a 10 lbm is measured at a location where g = 32.1 ft/sec^2 on a spring scale originally calibrated in a region wjere g = 32.2 ft/sec^2. What will be the reading? Ans 9.91 lbf
Mainly I think I know how to calculate this, but since it is in the accursed english system, I need it explained to me. Basically I take the ratio of the gravity values, and multiply that to the 10 lbm to get a new theoretical lbm, and then multiply that by 32.1 ft/sec^2 and divide by 32.2 ft/sec^2 to get 9.907 lbf or so which rounds to 9.91, but am I really doing this right? Please explain.
Explanation / Answer
The acceleration of gravity in the region where the spring scale calibrated g1 = 32.2
The acceleration of gravity in the region where the weight of the object is measured g2 = 32.1
Wm = 10*g2/g1
Wm = 10 * 32.1/32.2
Wm = 9.97 lbf
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