Three identical metal spheres are hung from a calling on rigid non-conducting ro

Question

Three identical metal spheres are hung from a calling on rigid non-conducting rods. Sphere 1, sphere 2, and sphere 3 have charge 33mu C, -50 mu C and 52 mu C, respectively. Each sphere is separated by 15 cm. What is the net electric force on the middle sphere due to spheres 1 and 3? (Enter the magnitude only). How do you calculate the electric force? If the spheres all lay along the same line, how do you calculate the net force? Did you convert all your units to SI? N What is the direction of the net electric force?

Explanation / Answer

net F = kQq / d²

net F = 8.99e9N·m²/C² * 50e-6C * (33e-6C - 52e-6C) / (0.15m)²
We have subtracted it As, the 33 µC charge is going to pull sphere 2 to the right (positive) and the 52 µC sphere is going to pull sphere 2 to the left (negative).

net F = -379.57 N
That is, 379.57 N to the left, toward sphere 1.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.