In an old-fashioned amusement park ride, passengers stand inside a 3.50 m tall,

Question

In an old-fashioned amusement park ride, passengers stand inside a 3.50 m tall, 6.10 m diameter hollow steel cylinder with their backs against the wall. The cylinder begins to rotate so that the riders travel in a horizontal circle. When the ride is rotating fast enough, the floor on which the passengers are standing suddenly drops away! If all goes well, the passengers will “stick” to the wall and not slide down. Clothing has a coefficient of static friction against steel in the range 0.60 to 1.0 and a kinetic coefficient in the range 0.40 to 0.70. What is the minimum speed that a person must be traveling to remain stuck to the wall without sliding?

Explanation / Answer

The normal force on the

N = mV2/R

for person to be in equilibrium

vertical forces should balance

Friction = gravitation force

u N = mg

u mV2/R = mg

V = sqrt (gR/u)

for value of V u should be minimum

there fore

V = 7.0617 m/sec

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.