i want a step by step explaination please because i am really bad at physics . t

Question

i want a step by step explaination please because i am really bad at physics . thank you

Part A

What are the ball's average velocity during the first 3.0 s ?

Express your answer using two significant figures.

Part B

What are the ball's average speed during the first 3.0 s ?

Express your answer using two significant figures.

Part C

Suppose that the ball moved in such a way that the graph segment after 2.0 s was -3.0 m/sinstead of +3.0 m/s. Find the ball's and average velocity during the first 3.0 s in this case.

Express your answer using two significant figures.

Part D

Suppose that the ball moved in such a way that the graph segment after 2.0 s was -3.0 m/sinstead of +3.0 m/s. Find the ball's average speed during the first 3.0 s in this case.

Explanation / Answer

Vavg = (2 + 2 + 3)/3 = 2.3 m/s

Speed = | Vavg |

Vavg = (2 + 2 - 3)/3 = 0.33 m/s

Speed = | Vavg |

c) (2*2-3*1)/3=0.333;d)(2*2+3*1)/3 = 2.3333

the balls average speed and velocity during the first 3s Vavg is similar to delx/delt delt=0 x=2m/s x0=0m delt=1s x=2m/sx(1s)=2m delt=2s x=2m del t=3s so x=3m

Speed is independent of direction of motion, but velocity changes sign if direction is reversed.

Distance = v*t = area under vt graph.

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