An ideal gas is enclosed in a cylinder with a movable piston on top of it. The p

Question

An ideal gas is enclosed in a cylinder with a movable piston on top of it. The piston has a mass of 8,000 g and an area of 5.00 cm^2 and is free to slide up and down, keeping the pressure of the gas constant. How much work is done on the gas as the temperature of 0.280 mol of the gas is raised from 10.0degreeC to 275degreeC? What does the sign of your answer to part (a) indicate? The surroundings do positive work on the gas. The gas does positive work on its surroundings. There is no work done, by the gas or the surroundings.

Explanation / Answer

Mass of piston = 8 kg
Area = 0.0005m2
Now pressure due to weight of the piston = force/ area = 8 * 9.8 / 0.0005 = 1.56*10,000 Pa
Pressure volume work at constant pressure = p dv => where dv is change in volume
now, from ideal gas equation, pv = nRT
for constant pressure, pdv = nRdT
so pdv = n * R * dT = 0.28 * 8.31 *( 275-10) = 616.602 J
This means gas does +ve work on the atmosphere as its volume is increasing

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