What are the strength and direction of the electric field at the position indica

Question

What are the strength and direction of the electric field at the position indicated by the dot in the figure? Give your answer in component form. (Assume that x-axis is horizontal and points to right, and y-axis points upward.) Express your answer in terms of the vector i vector and j vector. Express your answer using two significant figures. Give your answer as a magnitude and angle measured cw from the positive x-axis. Express your answer using two significant figures. E= 1.3*10^5 N/C Express your answer using two significant figures. theta = 148.65

Explanation / Answer

field due to -5nC = 5*10^-9*9*10^9/0.04^2 = 28125 along y-axis

vector form: E = 28125j

field due to 5nC = 5*10^-9*9*10^9/0.02^2 = 112500 along x-axis

vector form: E = 112500i

field due to 10nC = 10*10^-9*9*10^9*10000/20 = 45000 along diagonal

vector form: E = 45000*2/sqrt(20)i - 45000*4/sqrt(20)j=20124.61i - 40249.22j

net field = 20124.61i - 40249.22j

                   +112500i

                                     +28125j

               =132624.61i -1224.22j

              = 1.33*10^5 N/C at an angle of 5.223 deg clockwise from x-axis

angle in counter clockwise direction = 360-5.223 = 354.777 or 354.78 deg up two sig. digits

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