I attempted to use... C = 55(cos(20)-sin(20))+70(cos(42)+sin(42)) C = 131.7 A ve

Question

I attempted to use...

C = 55(cos(20)-sin(20))+70(cos(42)+sin(42))

C = 131.7

A vector A has a magnitude of 55.0 m and points in a direction 20.0° below the positive x axis. A second vector, B, has a magnitude of 70.0 m and points in a direction 42.0° above the positive x axis (a) Sketch the vectors A, B, and C = A + B. (Do this on paper. Your instructor may ask you to turn in this diagram.) This answer has not been graded yet. (b) Using the component method of vector addition, find the magnitude and direction of the vector C x m (counterclockwise from the positive x-axis)

Explanation / Answer

A = <55cos20.0°, -55sin20.0°> =<51.68, -18.81>

B = <70.0cos42°, 70.0sin42°> =<52.02, 46.84>

C = A + B
C = <51.68 + 52.02, -18.81 + 46.84>
C <103.7, 28.03> m

||C|| sqrt[(103.7)² + (28.03)²]
C 107.42 m

Angle=arctan(28.03/103.7)=15.13 deg

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