1) suppose that, in laboratory exercise, you add 0.355g of liguid to a 145.67-g

Question

1) suppose that, in laboratory exercise, you add 0.355g of liguid to a 145.67-g ceramic bowl. after you heat the liguid for 25.01 s, you measure the mass of the bowl and liquid together to be 145.82g. what was the average mass of liquid that evaporated each second?

2) the kentuchy Derby horserace is 1.000 mile and 440 yards long. express this distance in meters.

3) express the result of each of the following calculations to the correct number of significant digits:

a: (42.003)(1.3*10^4)(0.007000)

b:(42.003)(13,000)(0.007000)

c:(170.08bi)/32.6

d:113.7540 - 0.08

Explanation / Answer

1)Initially liquid mass = 0.335 g

After 25.01 s , mass = 145.82 - 145.67 = 0.15 g

Avg mass of liquid that evaporated = ( 0.335 - 0.15) / 25.01

= 0.0074 g/sec

2) 1 mile = 1609.34 meters

1 yard= 0,9144 meters

440 yards= 402.336 meters

Final distance in meters= 1609.34 + 402.336=2011.676 meters

3)

a)3822.273

with two significants digits

3822.27

b) 3822.273

c) 16.3819

with trherr significants digits

16.382

d) 113.674

with two significant digits

113.67

**do not know what bi means**

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