Like the Kelvin scale, the Rankine scale is an absolute temperature scale: Absol

Question

Like the Kelvin scale, the Rankine scale is an absolute temperature scale: Absolute zero is zero degrees Rankine (0R). However, the units of this scale are the same size as those on the Fahrenheit scale (F) rather than the Celsius scale (C).

A) Given that water at standard pressure freezes at 0C, which corresponds to 32F, and that it boils at 100C, which corresponds to 212F, calculate the temperature difference T in degrees Fahrenheit that corresponds to a temperature difference of 1 K on the Kelvin scale.

B) What is the numerical value of the triple-point temperature Ttriple of water on the Rankine scale?

Explanation / Answer

The temperature T in degrees Fahrenheit (°F) is equal to the temperature T in Kelvin (K) times 9/5, minus 459.67:

T(°F) = T(K) × 9/5 - 459.67

For a temperature difference of 1K in kelvin scale

T(°F) = 1× 9/5 - 459.67

         = -457.87 °F

The temperature T in Kelvin (K) is equal to the temperature T in Rankine (°R) times 5/9

Water triple point = 273.16 kelvin

value of the triple-point temperature of water on the Rankine scale = 273.16 *1.8

                                                                                                          =   491.688 °R

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