Entomology please describe how you got the answers Planning is being made to con
ID: 252300 • Letter: E
Question
Entomology
please describe how you got the answers
Planning is being made to control an invasive herbivorous insect along a peninsula. An insecticide barrier is laid across the northern and southern most landscape of the peninsula. The herbivorous insect has the following ecological characteristics. The initial population density of males and females has been estimated to be 200,000 insects, the rate of population increase is 2, the ratio of females to males is 1, and the females only mate once. To save money and accommodate limited rearing facilities, a constant release rate of 500,000 sterile males is made, giving an initial ratio of release of 5 infertile males to every 1 fertile males, which translates to a probability of successful mating of 0.167 l.?., 1 fertile mating for every 6 possible matings . Based on the initial population size, fill in the empty cells (i.e., Box 1-6) of the table to estimate how many generations of sterile male releases would be required to eliminate the invasive insect herbivore from the peninsula. The correct numbers (and their format) are in the following list: (Each correct answer is worth 2 pts; double check your answers to ensure that the format of the numbering is the same as that used in the list of possible answers) 800,000; 600,000; 500,000; 400,000; 300,000; 5,000; 4,800; 4167; 4053; 3091; 10; 0; 34; 2; 15; 7260:1; 8000:1; 6260:1; 5350:1 Generation Ratio No females if mal no sterile released releases No. sterile No. Equivalent females sterile tono. fertile with sterile releases normal females at males end of generation 100,000 500,000 100,0005:1 200,000 Box 2 400,000 500,000 Box 3 Box 1 16,667 2 15:1 120:1 Box 5 33,333 2083 Box 4 Box 6 4 500,000 69 Box 1 Box 6: , Box 2: ; Box 3: ; Box 4: Box 5Explanation / Answer
Box 1:
Rate of population increase = 2
No.females if no sterile release in generation 4 = Rate of population increase * No.females if no sterile release in generation 3 = 2 * 400000 = 800000
Box 1 = 800,000
Box 2:
No. of sterile males released is constant (500000) throughout all the generation.
Box 2 = 500,000
Box 3:
Ratio sterile to normal males = No. sterile males released/no. of females with sterile release = 120/1
=> 500000/no. of females with sterile release = 120/1
=> No. of females with sterile release =500000/120 = 4166.67 = 4167
Box 3 = 4167
Box 4:
Equivalent no.of fertile females at end of generation 3=No. of females with sterile release/(120+1)=4167/121=34.4
Box 4 = 34
Box 5:
Ratio of sterile to normal males = No. sterile males released/ No. of females with sterile release = 500000/69=7246
Ratio near ot 7246:1 = 7260:1
Box 5 = 7260:1
Box 6:
Equivalent no.of fertile females at end of generation 4=69/(7260+1)=69/7261 = 0.0095 = 0
Box 6 = 0
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