For each re on o the ac operon on the F plasmd. binding sequence) cr whether the

Question

For each re on o the ac operon on the F plasmd. binding sequence) cr whether the region is mistated Select all that apply. P ?Z delermine whether the ie ion is wild ype ial s it produces a unc onal prolein s a correct prolein In this problam you will oxplore how to solve problems involving partial diploid lac operon bacterial strains. Becterial strains that are partialy diploid" have two copies of the lac uperon because they aquired a plasriid carrying just the c opercn regon one ctromosome, and the other copy is n the F plasrid that ws introduced into the cell hy conugation Patie dploid genotypes are written with the F' segment first and the recipient chromosome next. copy of the e lac operon region s on the recipi ents bacterial ? The promoter sequence is corre ttunct onal The repressor protein is produced The operator sequence is corecutunctionel You create a lc operon partal diploid mtn this genatype Bets-galactosdase is produced trom the lac gene ? Pennease ts produced trom the lacy gene To determine whic need to first consider each genotype separalely, and then together. h genes are transcribed and under what conditions you VCorrect This lac operon?P+ 0? ?·yt has a normal promoter sequence. Of the two structural genes (eeZ and lacY) only iecY has a wild type sequence. In terms of regulalion in respoeto lactose, the operon makes functional repres), owever Ihe operalor sequence is mulaled (O ). Part B LIse the information frem Part A to determine how the operon is regulated for this genotype pY) > Operon is inducible: permease s produced only in the presence of lactose O Operon is constitutive; pemease is produced even when lactose is absent O Operon is repress ble pemease is cnly produced in the absence of actose O Operon is noninduxcible pemeese is never produced, even when lectose is present

Explanation / Answer

Use the information from part A to determine how the operon is regulated for this genotype (I+ P+ Oc Z? Y+):

B) Operon is constitutive; permease is produced even when lactose is absent.

For I+ P+ Oc Z? Y+ genotype, only lacY is wild-type sequence that means only permease is produced. The gene lacZ is mutated that means no functional enzyme is produced. The promoter sequence is normal, so there is a possibility that RNA polymerase transcribes the operon, and can able to produce permease. In terms of regulation, functional repressor (I+) is made; however the operator region is mutated (Oc). The operator sequence is altered. So, the repressor cannot bind to DNA and prevent transcription. Therefore, permease is able to be produced under all conditions; it is constitutively expressed.

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.