e Quiz Module 10 Quiz ASSIGNM X a https://eagleonline.hocs.edu/courses/58059/qui

Question

e Quiz Module 10 Quiz ASSIGNM X a https://eagleonline.hocs.edu/courses/58059/quizzes/218234/take EQ Seardc D | Question 9 10 pts An individual heterozygous for cystic fibrosis but with normal phenotype is called a [1]. D Question 10 10 pts B- black and b - brown. You have a black guinea pig of unknown genotype. You test- cross it with a brown guinea pig, and you observe both black and brown progeny in the F1. The black guinea pig must have which genotype? O BB O bb O Not enough information to tell

Explanation / Answer

9) An individual heterozygous for cystic fibrosis but having normal phenotype is called a carrier because it carriers diseased allele

10) The black Guinea pig must have the genotype of Bb because test cross is used to determine the genotype of dominant phenotype individual. Test cross is crossing dominant phenotype individual with bb. So, if both phenotypes can be observed then the black individual must have Bb genotype  

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.