Let\'s say you collected data on proportion of eggs laid on four different bean

Question

Let's say you collected data on proportion of eggs laid on four different bean species, and you want to look for significant differences among them. You would calculate 95% confidence intervals (CIs) for each bean type and see if they overlap each other or not. Non- overlapping 95% CIs would indicate differences in the proportion of eggs laid across bean types. You got a point estimate of 0.20 (p- hat) for the proportion of eggs laid on kidney bean, and had a total sample size of 900, what is the lower bounds of the 95% CI? Lower bounds of 95% CI: p-1.96 |p(1-p) 72 p ( 1-p) 72 Upper bounds of 95% CI: + 1.96 0.19 0.23 0.10 ? 0.20 0.90 0.17

Explanation / Answer

Option second that is 0.23 is correct answer.

Here according to given formula, lower bound of 95% Cl = P^ - 1.96 ? P^ (1 - P^)/ n where n= sample size

Thus, lower bound of 95% Cl = 0.20 - 1.96 ? 0.20 (1 - 0.20)/ 900

= -1.76 ? 0.20 X 0.8/ 900

= -1.76 ? 0.16/ 900

= -1.76 X 0.4/30

= -1.76 X 1.33 = 0.23   

Related Questions

Navigate

• Browse (All)
• Browse L
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.