6. Fill in table 1 with the information in table 2. Show all your steps in the s

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Question

6. Fill in table 1 with the information in table 2. Show all your steps in the space next to the table or under Table 2 (8 points). (Assumption: Before the mouse was put into the chamber, oxygen concentration was stabilized and same as time 0:00 in Table 2.) Table 1: Calculation of metabolic rate Mouse Reference 02 (%) ow 02 (%) Change in 02 (uUmL) Uptake (uL min) O2 uptake (uLg min Metabolic rate al.g min min Table 2:Change in O2 concentration with time after the mouse was put into the chamber Weight of the mouse- 30g Flow rate 400mL/min 00 19 0:05 17 10 16 15 15 0:20 15 0:25 15 30 15 The average amount of heat produced for each liter of oxygen consumed in metabolism is about 4.8kCal or 20.1 kjoules

Explanation / Answer

From Table 2, we see that % of O2 in chamber is 19% at time t = 0. So this is your reference oxygen pencentage.

Therefore, Reference O2% = 19%.

Now, after initial period from 0-15 min, the % of 2 in the chamber was stabilized at 15%, and this is the percentage of O2 you will have in the outflow from the chamber. Therefore, Outflow O2% = 15%.

Again from above calculation we see that the change in O2% in the chamber is Reference - Outflow = 19 - 15 = 4%. This is equal to 0.04 ml/ml or 40 µl/ml.

Now given the flow rate = 400 ml/min. Also, we have seen in above calculations that there is a change of 40 µl/ml in the chamber. Since this change in O2 is due to the uptake of O2 by mouse.

Therefore, O2 uptake = Flow rate x Volumetric change = 400 ml/min x 40 µl/ml = 16000 µl/min.

Now since the mouse weighs 30g.

Therefore, O2 uptake/g = 16000/30 = 533.33 µl/g-min

It is given that heat produced per liter of O2 = 4.8kCal or 20.1 kJ.

From above calculations, we know that O2 consumed/min = 533.33 µl/g-min.

Therefore, metabolic rate (in kCal/g-min) will be = 533.33 * 4.8/ 1000000 = 0.00256 kCal/g-min or 2.56 Cal/g-min (here please note that 1L is put as = 1000000 µl in the calculation).

Similarly we will calculate metabolic rate in kJ/g-min, which will be 533.33* 20.1/1000000 = 0.01 kJ/g-min or 10 J/g-min

Thanks!

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6. Fill in table 1 with the information in table 2. Show all your steps in the s

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