Question 8 and 9: In an island lizard population with 1000 individuals, throat c
ID: 26111 • Letter: Q
Question
Question 8 and 9: In an island lizard population with 1000 individuals, throat color is determinedby a single gene locus with two alleles producing two different colors: green and blue, with
green being dominant; 91% of the lizards have green throats.
8. Assuming Hardy-Weinberg equilibrium, what should be the frequency of
the blue allele in this population?
a. 0.09
b. 0.3
c. 0.6
d. 0.10
9. How many heterozygous individuals should you see in this lizard population?
a. 90 of the 1000 should be heterozygous (0.09%)
b. 420 of the 1000 should be heterozygous (42%)
c. 490 of the 1000 should be heterozygous (49%)
d. 810 of the 1000 should be heterozygous (81%)
10. BRCA1 and BRCA2 are known as tumor suppressor genes. A woman's risk of developing breast
and/or ovarian cancer is greatly increased if she inherits a deleterious (harmful) BRCA1 or BRCA2
mutation. Men with these mutated genes also have an increased risk of breast cancer. Both men
and women who have harmful BRCA1 or BRCA2 mutations may be at increased risk of other
cancers. It was recently discovered that the BRCA2 deleterious effect was recessive. On the
island of New Quinoa, in a population of 10 000 people, 5200 are homozygous for the normal
BRCA2 gene, approximately what percent of the population is at risk of passing on a cancerous
gene but not expressing one? Assume Hardy-Weinberg equilibrium.
a. 7.8%
b. 27.9%
c. 40.2%
d. 52.0%
Explanation / Answer
Question 8 and 9: In an island lizard population with 1000 individuals, throat color is determined
by a single gene locus with two alleles producing two different colors: green and blue, with
green being dominant; 91% of the lizards have green throats.
8.
Assuming Hardy-Weinberg equilibrium, what should be the frequency of
the blue allele in this population?
a. 0.09
b. 0.3
c. 0.6
d. 0.10
Blue Q^2= 90/1000
Q= 0.3
9. How many heterozygous individuals should you see in this lizard population?
a. 90 of the 1000 should be heterozygous (0.09%)
b. 420 of the 1000 should be heterozygous (42%)
c. 490 of the 1000 should be heterozygous (49%)
d. 810 of the 1000 should be heterozygous (81%)
=2PQ= 2 X0.7 X 0.3 X1000=420
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