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Key: A1:1-0.6 or 0.4 A2: sqrt(.36) or 0.6 (show work)

Assume that in a population of butterflies that is a gene located locus A that codes for body color and that there are two alleles found in this population: A1 which is dominant and produces a brown phenotype, and A2 which is recessive and produces a white phenotype. Using this information answer the following questions: What would be the phenotypes (brown or white) of the following genotypes (3) A1A1: A1A2: A2A2: If 36% of the population had the A2A2 phenotype, and the population was known to be in Hardy- Weinberg equilibrium, what would be the frequency of the following alleles in this population? (2) A1: A2:

Explanation / Answer

Given that the frequency of A2A2 is 36%= 0.36.

so, q2=0.36=> q= square root of 0.36=0.6

We know that sum of the alleles in a locus is 1.

Thus,

p+q=1.

So, p=1-q=1-0.6=0.4

p=0.4

q=0.6

Thus, A1=0.4

A2=0.6

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