Hardy-Weinberg Equilibrium Show all work for credit! p + q = 1 (Phenotypes) p^2

Question

Hardy-Weinberg Equilibrium Show all work for credit! p + q = 1 (Phenotypes) p^2 + 2pq + q^2 = 1 (Genotypes) 4. In a population of moths the color brown (B) is dominant over the color white (b). When you sample this moth population you find that out of the 500 individuals collected, 350 are brown and the rest are white. Given this, determine the following: A. The frequency of each allele. Remember to find p, not p2 . White allele (b) = Brown allele (B) = B. The frequency of each genotype (1 pt): Homozygous recessive (bb) = Homozygous dominant (BB) = Heterozygous (Bb) = C. The frequency of each phenotype (1 pt) White color = Brown color = 5. Birds begin to prey on the moths described above, but can

Explanation / Answer

Hardy-Weinberg Equilibrium Show all work for credit! p + q = 1 (Phenotypes)

p^2 + 2pq + q^2 = 1 (Genotypes)

4. In a population of moths the color brown (B) is dominant over the color white (b).                   

color brown (B) is dominant--p

color white (b).------------q

When you sample this moth population you find that out of the 500 individuals collected, 350 are brown and the rest are white. Given this, determine the following: A. The frequency of each allele

p^2 + 2pq=======350

q^2 =150

q^2 =150/500

q= square root of 150/500=0.547

hence p=1-0.547=0.453

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