. What is the minimum virus credit required from disinfection at a properly oper
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Question
. What is the minimum virus credit required from disinfection at a properly operated direct filtration plant? (3 points) a) 3 Logs, since to be in compliance 4 Logs should be achieved but at the first "barrier", i.e., physical removal, 1 Log credit is achieved. b) 2 Logs, since to be in compliance 4 Logs should be achieved but at the first "barrier", i.e., physical removal, 2 Log credit is achieved c) 1 Logs, since to be in compliance 4 Logs should be achieved but at the first barrier", i.e., physical removal, 3 Log credit is achieved. d) None of the above 300 ml volume of water contains 0.006 mg of THM. Express the concentration of HM in terms of ppb. (2 points) a) 20 ppb b) 40 ppb c) 30 ppb d) 50 ppb ong, rectangular settling basin is used for removing suspended solids during ter treatment. The basin's volume is desired to be 62,500 cubic feet and the len th ratio is to be maintained at 4:1 and its width-to-depth ratio at 1:1. Determine in's depth. (3 point ) 25 feet 35 feet 55 feet None of the aboveExplanation / Answer
answer 1. A. Minimum logs of inactivation needed by disinfection is 3 and maximum logs of credit for physical removal is 1, by policy.
answer 2. A. Parts per billion is units in micrograms per litre. Here, 0.006mg/300ml is equivalent to 0.02mg/L or 20 ug/L. Thus, 20ppb
answer 3. A. In a rectangle, volume = L x B x H where L is the length, B is the breadth/width and H is the height/depth. Since b:h=1:1, it means both of them are in ratio 4:1 with length since one of them (not clear in question though whether depth/ width..photo not clear) has the said ratio. Therefore,
V = L.B.H
Consider x variable to remove the proportian between the three parameters,
62500 = (4x). (x). (x)
62500 = 4x3
x3 = 15625
x = 25.
we know that depth = width and both in this case will be 25 feet.
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