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Nathan and Nicole are saving for their daughter Jessica\'s college education. Je

ID: 2696935 • Letter: N

Question

Nathan and Nicole are saving for their daughter Jessica's college education. Jessica just turned 10at (t=0), and she will be entering college 8 years from now (at t=8). College tuition and expenses at State University are currently $14,500 a year, but they are expected to increase at a rate of 3.5% a year. Jessica should graduate in 4 years, if she takes longer or wants to go to graduate school, she will be on her own. Tuition and other costs will be due at the beginning of each school year (at t=8,9,10and11). So far, Nathan and Nicole have accumulated $15,000 in their college savings account at (t=0). Their long run financial plan is to add an additional $5,000 in each of the next 4 years (at t=1,2,3 and 4). Then they plan to make 3 equal annual contributions in each of the following years, t= 5,6 and 7. They expect their investment account to earn 9%. How large must the annual payments at t=5,6 and 7 be to cover Jessica's anticipated college costs?

Explanation / Answer

14 500 * ((1.035)^8) + 14 500 * ((1.035)^9) + 14 500 * ((1.035)^10) + 14 500 * ((1.035)^11) = 80 479

Tuition the beginning of t=8: 14 500 * ((1.035)^7) = 18 448.05

Tuition the beginning of t=9: 14 500 * ((1.035)^8) = 19 093.73

Tuition the beginning of t=10: 14 500 * ((1.035)^9) = 19 762.01

Tuition the beginning of t=11: 14 500 * ((1.035)^10) = 20 453.68

Before the studying begins:

from accumulations they have: 1 500 * 1.09^7 = 27 420.59

from regular additions: 5 000 * 1.09^7 + 5 000 * 1.09^6 + 5 000 * 1.09^5 + 5 000 * 1.09^4 = 32 276.7

Total = 59 697.3

Cash flows during studying:

t

we have

tuition

left (year's beginning)

result ((year's end)*1.09)

8

59697,31

18448,05

41249,26

44961,6934

9

44961,69

19093,73

25867,963

28196,07967

10

27196,08

19762,01

7434,07

8103,1363

11

8103,136

20453,68

-12350,5437

So we have to save 9 536.8858 additionally before the study begins (12 350.5437/(1,09^3)) by 3 equal contributions: X*(1,09^3) + X*(1,09^2) + X*1,09 = 9 536.8858, X = 2 292.12

t

we have

tuition

left (year's beginning)

result ((year's end)*1.09)

8

59697,31

18448,05

41249,26

44961,6934

9

44961,69

19093,73

25867,963

28196,07967

10

27196,08

19762,01

7434,07

8103,1363

11

8103,136

20453,68

-12350,5437


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