A noted psychic was tested for ESP. The psychic was presented with 400 cards fac

Question

A noted psychic was tested for ESP. The psychic was presented with 400 cards face down and asked to determine if each card was matched with one of four symbols: a star, cross, circle, or square. The psychic was correct in 120 cases. Let prepresent the probability that the psychic correctly identifies the symbol on the card in a random trial. How large a sample n would you need to estimate p with margin of error 0.01 with 95% confidence? Use the guess p = 0.25 as the value for p.

n = 1351

n = 7203

n = 9604

n = 1351

n = 7203

n = 9604

Explanation / Answer

n = [ (z2 * p * q ) + ME2 ] / [ ME2 + z2 * p * q / N]

THE BELOW CALCULATION IS DONE USING A POPULATION SIZE OF 400.

Margin error 0.01 Confidence level 0.95 Alpha is 1-0.95 0.05 Z score is 1-alpha/2 0.975 Zvalue 1.96 p 0.25 N 400

n = [ (z2 * p * q ) + ME2 ] / [ ME2 + z2 * p * q / N]

THE BELOW CALCULATION IS DONE USING A POPULATION SIZE OF 400.

379.0082862

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