We will derive a two-state put option value in this problem. Data: Sq = 110; X =
ID: 2714764 • Letter: W
Question
We will derive a two-state put option value in this problem. Data: Sq = 110; X = 120; 1 + r= 1.1. The two possibilities for S7 are 140 and 100. The range of S is 40 while that of P is 20 across the two states. What is the hedge ratio of the put? (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.) Form a portfolio of 2 shares of stock and 4 puts. What is the (nonrandom) payoff to this portfolio? (Round your answer to 2 decimal places.) What is the present value of the portfolio? (Round your answer to 2 decimal places.) Given that the stock currently is selling at 110, calculate the put value. (Round your answer to 2 decimal places.) Use the Black-Scholes formula to find the value of a call option on the above stock: Calculate the value of a call option. (Do not round intermediate calculations. Round your answer to 2 decimal places.)Explanation / Answer
Answer-1:
Two-state put option
S = 110; X=120; 1+r = 1.1
The stock price today is $110, At the end of the year, stock price will be either $140 or $100
If the stock price increase to $140, put option will not be exercised so payoff =0
If the stock price decreases to $100, put option will pay $20 (i.e. buy the stock in the open market for $100 and exercise the put option to sell the stock for X=120)
The hedge ratio (ratio of put option payoffs to stock payoffs)
= (0-20)/(140-100) = -20/40 = -2/4
So I will create the following portfolio
CF today CF one year from today
If S=140 If S=100
Buy 2 Shares -220 2*140 = $280 2*100 = $200
Buy 4 puts -4P 0 4*20 = $80
TOTAL -(220+4P) $280 $280
Since the payoff is the same in either outcome, this is a riskless portfolio which should earn 10% rate of return. So the most I would be willing to pay for it today is the present value of $390 discounted at 10%
= 280/(1.1) = $254.54
In equilibrium, 220+4P = 254.54 So P = $8.63
Answer-2:
Using the Black-Scholes option pricing model to find the price of the call option, we find:
d1 = [ln($50/$50) + (0.03 + 0.502/2) x (6/12)] / (0.50 x (6/12)1/2 ) = 0.02121
d2 = 0.02121 – (0.50 x (6/12)1/2 ) = –0.332396
N(d1) = 0.5080
N(d2) = 0.3707
Putting these values into the Black-Scholes model, we find the call price is:
C = $50(0.5080) – ($50e–0.03(0.5))(0.3707) = $6.583
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