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QuestionDetails: hello please resolve and explain in a punnett in horses black i

ID: 2737 • Letter: Q

Question

QuestionDetails: hello please resolve and explain in a punnett in horses black is due to a dominant gene and chestnutto its recessive allele. a black mare mated to a black stallionproduces a chestnut colt. if they produce another offspring. could it be black? if so, what are the chances of its being black?list the genotypes of all the animals mentioned in thisproblem? problem number 2 an albino man marries a normally pigmented woman they havenine children , all normally pigmented waht are the probable genotypes of the parents adn thechildren? QuestionDetails: hello please resolve and explain in a punnett in horses black is due to a dominant gene and chestnutto its recessive allele. a black mare mated to a black stallionproduces a chestnut colt. if they produce another offspring. could it be black? if so, what are the chances of its being black?list the genotypes of all the animals mentioned in thisproblem? problem number 2 an albino man marries a normally pigmented woman they havenine children , all normally pigmented waht are the probable genotypes of the parents adn thechildren? QuestionDetails: hello please resolve and explain in a punnett in horses black is due to a dominant gene and chestnutto its recessive allele. a black mare mated to a black stallionproduces a chestnut colt. if they produce another offspring. could it be black? if so, what are the chances of its being black?list the genotypes of all the animals mentioned in thisproblem? problem number 2 an albino man marries a normally pigmented woman they havenine children , all normally pigmented waht are the probable genotypes of the parents adn thechildren?

Explanation / Answer

The two animal have a Bb genotype because its the only way thecould be black and still produce a chestnut colt B b B BB (Black) Bb (Black) b Bb (Black) bb (chestnut) B b B BB (Black) Bb (Black) b Bb (Black) bb (chestnut)
so by the chart you could have a black colt and you would have a3:1 chance (75%) of having it problem number 2 (N=nomal skin) N N n Nn Nn n Nn Nn man has nn women has NN all the kids would then have Nnskin B b B BB (Black) Bb (Black) b Bb (Black) bb (chestnut)
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