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I need help solving this one my molecular biology exam starts after 4 hours Than

ID: 274028 • Letter: I

Question

I need help solving this one my molecular biology exam starts after 4 hours
Thanks in advance

This section consists of 1 discussion question. Take the time to read and answer the questions carefully. You will be awarded 5 marks for this section. Below is a schematic of gene h, which encodes protein H The promoter region is indicated by the dotted box. Transcription begins immed iately following the promoter Preegtes Traaipenal teemthatue 5100 he 2200 1- The transcript first produced by this gene would be approximstely how many nucleotides long? (1 mark) bo 2- Two different transcripts are produced from thie genc: one is approximately 2000 nucleoides long, the other is approximately 3000 nucleotides long Explain how 2 different transcripts can be produced from this gerne? (1mark) Assume that each Iranscript produces a protein. Accrding to the above diagrarm and your answers, what is the approximate size of the two proteins produced from th s gene? (2 marks 3-

Explanation / Answer

1. If all exons of the gene corresponds to the same full length gene, the length of the primary transript if it comes out as a single transcript (the one produced immediately after transcription and does not undergo RNA splicing) would be approximately 5100 bp long. After primary transcript being processed, the transcript of certain sizes encoding various proteins will be produced.

2. Presence of transcription regulators like repressors would inhibit the activity of RNA polymerase and lead RNA polymerase to dissociate from the entire transcription complex.. Presence of certain DNA sequences called silencers that bind to factors may contribute to the destabilization of initiation complex thus inhibiting transcription.

3. If each transcript produces a protein, considering the splicing reaction to get rid of introns and each exon contributes to encoding a protein, the protein size would be as follows approximately.

Exon1= 1000 nucleotides= 333 amino acids (protein 1 size)

Exon 2+Exon 3= 1000+1000 nucleotides= 2000 nucleotides= 666 amino acids approximate (protein 2 size).

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