the figure below illustrates a metabolic pathway for coat color in mice. Agouti
ID: 274130 • Letter: T
Question
the figure below illustrates a metabolic pathway for coat color in mice. Agouti is dominant to black or non-agouti hair, which resuls from the homozygous expression of a recessive mutation a. When a recessive mutation, b, at a separate locus is homozygous, it eliminates pigmentation altogether, yielding albino mice. If you cross a true-breeding albino mouse with a true-breeding agouti mouse, and then cross the resultant F1 animals with themselves, what phenoypic ratio of agouti: black:albino: do you expct to see in the F2?
The figure below illustrates a metabolic pathway for coat color in mice. Agouti is dominant to black, or non-agouti hair, which results from the homozygous expression of a recessive mutation a. When a recessive mutation, b, at a separate locus is homozygous, it eliminates pigmentation altogether, yielding albino mice Precursor Gene B Black Molecule product pigment product pigment (colorless) Gene A Agouti 49. Ifyou cross a true-breeding albino mouse with a true-breeding agouti mouse, and then cross the resultant F1 animals with themselves, what phenotypic ratio of agouti: black: albino do you expect to see in the F2? a. 9:6:1 b. 9:1:6 c. 9:3:4 d. 9:4:3 e. 12:1:6 f. 12:6:1 50. What is the phenotype of AABb? a. Albino b. Black c. AgoutiExplanation / Answer
true breeding Agouti mouse = AABB
true-breeding albino mouse = aabb
AABB x aabb = AaBb (F1 generation).
AaBb x AaBb
A--B-- = Agouti (9)
aaB-- = Black (3)
A--bb = Albino (4)
option C.
2) AABb will be Agouti in color. because
A and B produces agouti
aaB(B/b) produces black and A(A/a)bb produces Albino mouse.
AB Ab aB ab AB AABB AABb AaBB AaBb Ab AABb AAbb AaBb Aabb aB AaBB AaBb aaBB aaBb ab AaBb Aabb aaBb aabbRelated Questions
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