Table 1 Codon on mRNA and corresponding amino acid AUG methionine UAA stop UUA l

Question

Table 1 Codon on mRNA and corresponding amino acid AUG methionine UAA stop UUA leucine GCA alanine AAG lysine GUU valine AAU asparagine UGC cysteine UCG serine UCU serine 35. (Use Table 1 above) What is the sequence of amino acids coded for by the following sequence of bases in a s DNA (hint, it must be transcribed into mRNA first)? 3'-TACTTAACGCAAATT-5 a. Methionine-valine-lysine-alanine b. Methionine-serine-lysine-alanine c. Methionine-asparagine-cysteine-valine d. Asparagine-cysteine-valine-serine e. Transcription would stop at the first codon 36. Under which of the following conditions will the expression (transcription) of the lac operon be the highest? a. Lactose present/glucose present b. Lactose present/glucose absent c. Lactose absent/glucose present d. Lactose absent/ glucose absent e. Both A and B are equivalent

Explanation / Answer

Ans 35 : c) Methionine-asparagine-cysteine-valine

The codons on mRNA have nucleotide sequence complimentary to the DNA strand. So here , the mRNA strand will be :

5'-AUGAAUUGCGUUUAA-3'

So according to this , the amino acid sequence will be :

Methionine-asparagine-cysteine-valine

So the correct option is c

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