1. Lei die aminosuurvolgorde van \'n peptied af uit die volgende data:/ Deduce t
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1. Lei die aminosuurvolgorde van 'n peptied af uit die volgende data:/ Deduce the amino acid sequence of a peptide from the following data: (a) Suur-hidrolise gee: Met, Tyr, Ser, Phe, Gly, Lys, Ala. Acid hydrolysis yields: Met, Tyr, Ser, Phe, Gly. Lys, Ala. (b) Edman se reagens lewer PTH-Lys./ Edman's reagent yields PTH-Lys (c) CNBr gee 'n dipeptied wat Lys en homoserien bevat en 'n tweede peptied wat die res van die aminosure bevat. CNBr yields a dipeptide containing Lys and homoserine and a second peptide containing the rest of the amino acids. Gly word vinnig vrygestel tydens behandeling met karboksipeptidase A./ Gly is liberated with a high initial rate during treatment with carboxypeptidase A (d) (e) Kimotripsien lewer 3 peptiede: een bevat Tyr, Lys, Met: die tweede Ala, Gly en die derde Ser, Phe./ Chymotrypsin yields 3 peptides: one contains Tyr, Lys, Met. The second one contains Ala and Gly while the third one contains Ser and Phe.Explanation / Answer
Edman's reaction releases amino terminal amino acid from the peptide. CNBr yields dipeptide containing Lys and homoserine. Carboxypeptidase A releases aminoacid from the carboxy terminal. So, Gly is present at the carboxy terminal. Chymotrypsin cleaves the peptide bonds of tyrosine, phenylalanine and tryptophan. So, the amino acid sequence of the peptide is,
NH3 - Lys-Met-Tyr-Phe-Ser-Ala-Gly - COOH
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