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Genes A , B , and C are linked on a chromosome and found in the order A-B-C. Gen

ID: 278189 • Letter: G

Question

Genes A, B, and C are linked on a chromosome and found in the order A-B-C. Genes A and B recombine with a frequency of 9%, and genes B and C recombine at a frequency of 22%. For the cross

a +b +c/abc+ × abc/abc,
predict the frequency of progeny. Assume interference is zero.

a)Predict the frequency of a+b+c progeny.

Enter your answer to four decimal places (example 0.2356 or 0.2300).

B) Predict the frequency of abc+progeny.

Enter your answer to four decimal places (example 0.2356 or 0.2300)

Part C

Predict the frequency of a+bc+progeny.

Enter your answer to four decimal places (example 0.2356 or 0.2300)

Part D

Predict the frequency of ab+c progeny.

Enter your answer to four decimal places (example 0.2356 or 0.2300)

Part E

Predict the frequency of a+b+c+ progeny.

Enter your answer to four decimal places (example 0.2356 or 0.2300)

Part F

Predict the frequency of abc progeny.

Enter your answer to four decimal places (example 0.2356 or 0.2300)

Part G

Predict the frequency of a+bc progeny.

Enter your answer to four decimal places (example 0.2356 or 0.2300)


Predict the frequency of ab+c+progeny.Part H

Enter your answer to four decimal places (example 0.2356 or 0.2300)

Explanation / Answer

Answer:

A). The frequency of a+b+c progeny= 0.3549

B)Tthe frequency of abc+progeny = 0.3549

C) The frequency of a+bc+progeny = 0.0351
D) The frequency of ab+c progeny = 0.0351

E) The frequency of a+b+c+ progeny = 0.1001

F) The frequency of abc progeny = 0.1001

G) The frequency of a+bc progeny = 0.0099

H). The frequency of ab+c+progeny = 0.0099

Explanation:

Class of gametes

Phenotype

Frequency of reciprocal pair

Numbers

Frequency of each class

Parental

a+ b+ c

1- all recombinant progeny

1-(0.0702+0.2002+0.0198) = 0.7098

0.3549

a b c+

0.3549

SCO 1

a+ b c+

RF in region 1 = SCO1 - DCO

SCO1 = 0.09 – 0.0198 = 0.0702

0.0351

a b+ c

0.0351

SCO 2

a+ b+ c+

RF in region 2 = SCO2 - DCO

SCO2 = 0.22 – 0.0198 = 0.2002

0.1001

a b c

0.1001

DCO

a+ b c

(RF in region 1) * (RF in region 2)

0.09 * 0.22 = 0.0198

0.0099

a b+ c+

0.0099

  

Class of gametes

Phenotype

Frequency of reciprocal pair

Numbers

Frequency of each class

Parental

a+ b+ c

1- all recombinant progeny

1-(0.0702+0.2002+0.0198) = 0.7098

0.3549

a b c+

0.3549

SCO 1

a+ b c+

RF in region 1 = SCO1 - DCO

SCO1 = 0.09 – 0.0198 = 0.0702

0.0351

a b+ c

0.0351

SCO 2

a+ b+ c+

RF in region 2 = SCO2 - DCO

SCO2 = 0.22 – 0.0198 = 0.2002

0.1001

a b c

0.1001

DCO

a+ b c

(RF in region 1) * (RF in region 2)

0.09 * 0.22 = 0.0198

0.0099

a b+ c+

0.0099