Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Punnett\'s square analysis for the parental cross r Rr Rr 9) If we used the abov

ID: 278239 • Letter: P

Question

Punnett's square analysis for the parental cross r Rr Rr 9) If we used the above offspring (F1) in a new cross, what would be the genotypes and phenotypes of the offspring of the Fz generation? 10) What is the genotypic ratio of the F2 generation? 11) What is the phenotypic ratio of the F2 generation? 12) What would be the genotypic and phenotypic ratios of offspring from a cross between a homozygous recessive parent (r r) and a heterozygous parent (R r)? 13) The ear of corn in front of you (#1) is from the F2 generation of a controlled cross. Using what you now know about Punnett's squares, monohybrid crosses, and phenotypic/genotypic ratios, how could you determine the genotype and phenotype of the Fi parents? 14) What is the phenotype and genotype of the Fi parents using your method from the above question? 15) what is the phenotype and genotype of the F1 parents of corn #2? B. Mendel's Law of Independent Assortment: When the alleles of two different genes separate during meiosis, they do so independently of one another unless the genes are located on the same chromosome (linked). This is the principle of independent assortment. Mendel discovered independent assortment by performing dihybrid crosses in the pea plant. We will examine dihybrid crosses in maize. Consider the genes for kernel color and kernel composition in maize. Seed color gene R allele, dominant, for purple kernels r allele, for yellow kernels Seed composition gene T allele, dominant for smooth (starchy) kernels t allele, for wrinkled (sweet) kernels In the P generation, a homozygous plant with purple, smooth kernels was crossed with a plant having yellow wrinkled kernels. The F, plants were allowed to fertilize themselves. According to the principle of independent assortment, the color gene and the seed shape gene should not affect one another; that is, they should behave independently.

Explanation / Answer

Answering 9-15 parts:

The given parental cross leads to F1 generation:

Punnett Square:

All the progeny of F1 generation has genotype Rr (heterozygous):

9) The cross Rr x Rr can be represented as a Punnett Square below:

10) Genotypic Ratio Obtained: RR : Rr : rr = 1 : 2 : 1

11) Phenotypic Ratio Obtained: RR and Rr will have the same phenotype (Purple). Therefore, the Phenotypic ratio is: 3 : 1

12) Given cross is: Homozygos recessive parent (rr) x Heterozygous parent (Rr)

Punnett Square:

13) A test cross (a genetic cross between a homozygous recessive individual and a corresponding suspected heterozygote) can be used to determine the genotype and phenotype of the F1 parent.

14) What is the phenotype and genotype of the F1 parents using your method from the above question?

Rr x rr

Phenotypic Ratio is Purple : Yellow (1:1), which indicates that Genotype of parent is Rr

15) What is the phenotype and genotype of the F1 parents of corn #2? ** Please share details of Corn#2

R R r Rr Rr r Rr Rr
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote