Not sure if what I did is correct, please explain. This question has 5 parts- it
ID: 279293 • Letter: N
Question
Not sure if what I did is correct, please explain. This question has 5 parts- it is considered 1 question since the material builds on each other.Thank you! During your analysis you discover a new electron transport chain ba 0.5 V Ickygreenone +H +2e Ickygreenol Barsoom + H +2eBarsool is the reductant for the proposed ETC? a) Ickygreenol 9. Whichs Barsoom c) Barsool d) Ickygreenone 10. Which species is the oxidant for the proposed ETC? a) Ickygreenol b) Barsoom CBarsool 11. Which series of voltages represents the correct voltages to trace the electron flow for the free energy alculation? b) +0.5V and-1.25V C)-0.5V oses guins .What is the free energy gained from the electron transport chairn a) -34.5 kcal/mol b) +80.5 kcal/mol c) 334.5 kcal/mol -80.5 kcal/mol e) It cannot be determined from the information given. From one run of the proposed electron transport chain oretically be generated? , how many ATP equivalents in energy could c) 5 7.3
Explanation / Answer
9. c. Bansool
More the positive value of potential, the more likely the substance is to be reduced.
Here,
Ickygreenone + H+ + 2e- gives Ickygreenol (-0.5V) : reduction reaction
Bansool gives Bansoom + H+ + 2e- (+1.25) : oxidation reaction [reversed the reaction, so potential positive]
Ickygreenone+ H+ + 2e- + Bansool GIVES Ickygreenol + Bansoom + H+ + 2e-
Cancel the common terms, we get:
Ickygreenone + Bansool GIVES Ickygreenol + Bansoom : overall reaction
Ickygreenone is getting electrons from Bansool and getting reduced ; Bansool is reducing agent / reductant
Bansool looses electrons and getting oxidized ; Ickygreenone is oxidized agent / oxidant
Electrons flow from the reductant (oxidized form) of a redox couple with a lower electron affinity and a lower (more negative) potential to the oxidant of another redox couple having a higher electron affinity and a higher (positive or less negative) potential.
10. d. Ickygreenone
This oxidant gets reduced accepting electrons.
11. c. -0.5V and +1.25V
Difference in voltage (highest-lowest) is (+1.25) - (-0.5) = +0.75
electron flow is from lower (more negative) potential to higher (less negative) potentail.
12. a. -34.5kcal/mol
Free energy, Delta G= -nFdeltaE
= -2 X 23.063 X 0.75 = -34.59kCal/mol
free energy is always negative for a spontaneous reaction.
13. c. 5
-7.3kCal/mol is needed for the formation of 1 ATP molecule (high energy phosphate bond).
34.59 / 7.3 = 4.7 approximately 5.
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