MECH 402 Engineering Economics The cash flows for three mutually exclusive alter
ID: 2794300 • Letter: M
Question
MECH 402 Engineering Economics The cash flows for three mutually exclusive alternatives are given in table below. MARR-4%. cost Annual benefits $4,500 7,600 RoR IF Problem 1 ARoR for the first increment (Alt, C-Alt. A) is A. 3.36% B. 3.09% C. 2.85% D. 3.62% Solution: Problem 2 Determine the ARoR for the second increment (Alt. B-AltA) if A was retained during the first A. 10.85% incremental analysis. B. 8.12% -CA19% D. 5.78% Problem 3 The best alternative for a MARR of 2.0% using the incremental rate of return analysis is A. Alt. C B. Alt. A C.Alt. B D. Do-nothing F9Explanation / Answer
problem 1 AROR for the increment ( C - A ) years 0 1 2 3 4 5 c , cash flows -24000 6500 6500 6500 6500 6500 a , cash flows -15000 4500 4500 4500 4500 4500 incremental cash flows -9000 2000 2000 2000 2000 2000 internal rate of return using excel .=irr( cash flows form year 0 to 5 ) 3.62% answer d . 3.62 % problem 2 AROR for the increment ( B - A ) years 0 1 2 3 4 5 b , cash flows -27000 7600 7600 7600 7600 7600 a , cash flows -15000 4500 4500 4500 4500 4500 incremental cash flows -12000 3100 3100 3100 3100 3100 internal rate of return using excel .=irr( cash flows form year 0 to 5 ) 9.19% answer c . 9.19 % problem 3 the best alternative for a MARR of 2 % using the incremental rate of return is alternative 2 , because its incremental rate of return 9.19 % is more than the rate of return of 4 %
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