a man and women each have dark eyes, dark hair and freckles. The genes for these

Question

a man and women each have dark eyes, dark hair and freckles. The genes for these trails are on separate chromosomes. The women is heterozygous for each of these genes, but the man is homozygous. The dominance relationships of the alleles are as follows:

B=dark eyes; b=blue eyes; H=dark hair; h=blond hair; F=freckles; f=no freckles

a) What is the probability that their child will share the parents' phennotype?

b) What is the probability that the child will share the same genotype as the mother? as the father?

Use the product rule or a Punnet square to obtain your answer.

Explanation / Answer

Mother' s genotype : BbHhFF

Father's genotype : BBHHFF

Gametes of mother : BHF ; BhF ; BHf; Bhf ; bhf ; bHf ; bhF ; bHF

Gametes of father : BHF

a) there is 100 % probability that their child will parent's phenotype.

b) probability of child will have the same genotype as of mother = 1/ 8

And of father = 1/ 8

Total probability of the child having same genotype as of parent's = 1/ 8 × 1/8 = 1/ 16

Mother / father BHF BHF BBHHFF BhF BBHhFF BHf BBHHFf Bhf BBHhFf bhf BbHhFf bHf BbHhFf bhF BbHhFF bHF BbHHFF

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