04 (4pts) Assume that glucose can be oxidized by microbes using either oxygen ni
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04 (4pts) Assume that glucose can be oxidized by microbes using either oxygen nitrate, or sulfate Identity all four as either an electron donor or terminal electron acceptor and list the three reactions in order from most energetically favorable to least avorable MOST favorable to LEAST favorable 05 (6pts) A) Define/describe the Monod equation and define S, Ks, u. and umax B) Ks and umax can vary for different species (given the same metabolic reaction and environmental conditions) When substrate concentration is low (oligotrophic environment), is there an advantage to having a smaller or larger Ks? Briefly explain why C) when substrate concentration is much lower than Ks, how would you expect growth rate to compare to umax? Why? ,06 (4pts) Describe the use of the culture collection in interpreting an uncultured 16S rRNA sequence / Q7 (5 pts) If you were examining the changes in cyanobacterial activity that occurs between day and night would you use A) cloning sequencing and phylogenetic analysis of 16S rRNA genes, B) metagenomics C) metatranscriptomics, clearly explain why and what you would expect to find in the data Q8 (5pts) Pretend that you are an environmental microbiologist employed by a consulting firm hired to create a bioremediation plan for an aromatic carbon pollutant in soil at a former industrial site. As a first step your manager has asked you to isolate bacteria from the site's soil that would be capable of degrading the pollutant Describe the microbial growth media you would design and the steps you would take to enrich and isolate a pure culture capable of degrading the pollutant Describe why you would take each stepExplanation / Answer
Q4. Electron donor: Glucose
Terminal electron acceptor: Oxygen, Nitrate, Sulfate
For most favorable and least favorable reaction identification we have to look into the free energy value. More free energy release (-ve value) indicates that the reaction will go more forward direction. Means the reaction will be more favorable.
Most favourable : C6H12O6 + 6O2 = 6CO2 + 6H2O [delta Go = -686 kcal/mol]
Moderately favourable : CH2O + NO3- + 2H+ = CO2 + 1/2 N2 + 2H2O [delta Go = -649 kcal/mol]
Least favourable : 2CHO + SO42- + 3H+ = 2CO2 + HS- + 2H2O [delta Go = -190 kcal/mol]
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