Question 20 (1 point) Given a population of leafhoppers that are in Hardy-Weinbe

Question

Question 20 (1 point) Given a population of leafhoppers that are in Hardy-Weinberg equilibrium for two unlinked genes, each with two alleles. One of the genes has a mutant allele that causes shortened legs. The more common long-legged phenotype is found in 99% of the population. The second gene has a mutant allele that affects electrophoretic mobility of the lactate dehydrogenase (LDH) enzyme. The slow-mobility alleles is homozygous in only 16% of the leafhoppers. What proportion of the population is expected to have both the short-legged phenotype and be heterozygous for the mobility alleles of Ldh? Save Page 20 of 47 Previous Page Next Page

Explanation / Answer

A population of leafhoppers are in Hardy-Weinberg equilibrium for two unlinked genes. The long legged phenotype is present in 99% of the population. So, the short legged phenotype is present in 1% of the population.

P^2 +2pq + q^2 = 1

0.99 + q^2 = 1

q^2 = 0.01

q = 0.1

The slow mobility alleles is present in 16% of the population

q^2 = 0.16

So, q = 0.4 and p = 0.6

The proportion of heterozygous population is,

2pq

= 2(0.6)(0.4)

= 0.48

The proportion of population that is expected to have both short legged phenotype and heterozygous for the mobility alleles is,

= 0.01 × 0.48

= 0.0048

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.